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contourThis package draws contour lines.
To construct contours for a function f, use
guide[][] contour(real f(real, real), pair a, pair b,
real[] c, int nx=ngraph, int ny=nx,
interpolate join=operator --);
The contour lines c for the function f are drawn
on the rectangle defined by the bottom-left and top-right points a
and b. The integers nx and ny define the resolution.
The default resolution, ngraph x ngraph (here ngraph
defaults to 100), can be increased for greater accuracy. The
default interpolation operator is operator -- (linear). Spline
interpolation (operator ..) generally produces more
accurate pictures, but as usual, can overshoot in certain cases.
To construct contours for an array of data values on a uniform two-dimensional lattice, use
guide[][] contour(real[][] f, real[][] midpoint=new real[][],
pair a, pair b, real[] c,
interpolate join=operator --);
To construct contours for an array of irregularly spaced points
and an array of values f at these points, use one of the routines
guide[][] contour(pair[] z, real[] f, real[] c,
interpolate join=operator --);
guide[][] contour(real[] x, real[] y, real[] f, real[] c,
interpolate join=operator --);
The contours themselves can be drawn with one of the routines
void draw(picture pic=currentpicture, Label[] L=new Label[],
guide[][] g, pen p=currentpen)
void draw(picture pic=currentpicture, Label[] L=new Label[],
guide[][] g, pen[] p)
The following simple example draws the contour at value 1
for the function z=x^2+y^2, which is a unit circle:
import contour;
size(75);
real f(real a, real b) {return a^2+b^2;}
draw(contour(f,(-1,-1),(1,1),new real[] {1}));
The next example draws and labels multiple contours for the function
z=x^2-y^2 with the resolution 100 x 100, using a dashed
pen for negative contours and a solid pen for positive (and zero) contours:
import contour;
import stats;
size(200);
real f(real x, real y) {return x^2-y^2;}
int n=10;
real[] c = new real[n];
for(int i=0; i < n; ++i) c[i]=(i-n/2)/n;
pen[] p=sequence(new pen(int i) {
return (c[i] >= 0 ? solid : dashed)+fontsize(6);
},n);
Label[] Labels=sequence(new Label(int i) {
return Label(c[i] != 0 ? (string) c[i] : "",Relative(unitrand()),(0,0),
UnFill(1bp));
},n);
draw(Labels,contour(f,(-1,-1),(1,1),c),p);
The next example illustrates how contour lines can be drawn on color density images:
import graph;
import palette;
import contour;
size(10cm,10cm,IgnoreAspect);
pair a=(0,0);
pair b=(2pi,2pi);
real f(real x, real y) {return cos(x)*sin(y);}
int N=200;
int Divs=10;
int divs=2;
defaultpen(1bp);
pen Tickpen=black;
pen tickpen=gray+0.5*linewidth(currentpen);
pen[] Palette=BWRainbow();
scale(false);
bounds range=image(f,Automatic,a,b,N,Palette);
xaxis("$x$",BottomTop,LeftTicks,Above);
yaxis("$y$",LeftRight,RightTicks,Above);
// Major contours
real[] Cvals;
Cvals=sequence(11)/10 * (range.max-range.min) + range.min;
draw(contour(f,a,b,Cvals,N,operator ..),Tickpen);
// Minor contours
real[] cvals;
real[] sumarr=sequence(1,divs-1)/divs * (range.max-range.min)/Divs;
for (int ival=0; ival < Cvals.length-1; ++ival)
cvals.append(Cvals[ival]+sumarr);
draw(contour(f,a,b,cvals,N,operator ..),tickpen);
palette("$f(x,y)$",range,point(NW)+(0,0.5),point(NE)+(0,1),Top,Palette,
PaletteTicks(N=Divs,n=divs,Tickpen,tickpen));
Finally, here is an example that illustrates the construction of contours from irregularly spaced data:
import contour;
size(200);
int n=100;
pair[] points=new pair[n];
real[] values=new real[n];
real r() {return 1.1*(rand()/randMax*2-1);}
for(int i=0; i < n; ++i)
points[i]=(r(),r());
real f(real a, real b) {return a^2+b^2;}
for(int i=0; i < n; ++i)
values[i]=f(points[i].x,points[i].y);
draw(contour(points,values,new real[]{0.25,0.5,1},operator ..),blue);
In the above example, the contours of irregularly spaced data are constructed by
first creating a triangular mesh from an array z of pairs,
using Gilles Dumoulin's C++ port of Paul Bourke's triangulation code:
int[][] triangulate(pair[] z);
size(200);
int np=100;
pair[] points;
real r() {return 1.2*(rand()/randMax*2-1);}
for(int i=0; i < np; ++i)
points.push((r(),r()));
int[][] trn=triangulate(points);
for(int i=0; i < trn.length; ++i) {
draw((points[trn[i][0]])--(points[trn[i][1]]));
draw((points[trn[i][1]])--(points[trn[i][2]]));
draw((points[trn[i][2]])--(points[trn[i][0]]));
}
for(int i=0; i < np; ++i)
dot(points[i],red);
The example Gouraudcontour illustrates how to produce color
density images over such irregular triangular meshes.